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A = angle A

B = angle B

C = angle C

a = side a

b = side b

c = side c

P = perimeter

s = semi-perimeter

K = area

r = radius of inscribed circle

R = radius of circumscribed circle

Each calculation option, shown below, has sub bullets that list the sequence of methods used in this calculator to solve for unknown angle and side values including Sum of Angles in a Triangle, Law of Sines and Law of Cosines. These are NOT the ONLY sequences you could use to solve these.

**See also these Trigonometry Calculators:**

**AAA is Angle, Angle, Angle**- given the sizes of 2 angles of a triangle you can calculate the size of the third angle. The total will equal 180° or π radians.- C = 180° - A - B (in degrees)
- C = π - A - B (in radians)

**AAS is Angle, Angle, Side**- given the size of 2 angles and 1 side opposite one of the given angles, you can calculate the sizes of the remaining 1 angle and 2 sides.- use the Sum of Angles Rule to find the other angle, then
- use The Law of Sines to solve for each of the other two sides.

**ASA is Angle, Side, Angle**- given the size of 2 angles and the size of the side that is in between those 2 angles you can calculate the sizes of the remaining 1 angle and 2 sides.- use the Sum of Angles Rule to find the other angle, then
- use The Law of Sines to solve for each of the other two sides.

**ASS (or SSA) is Angle, Side, Side**- given the size of 2 sides (a and c where a < c) and the size of the angle A that is not in between those 2 sides you might be able to calculate the sizes of the remaining 1 side and 2 angles, depending on the following conditions.- For
**A ≥ 90° (A ≥ π/2)**:- If
**a ≤ c**there there are no possible triangles - Example:

- If
**a > c**there is 1 possible solution- use The Law of Sines to solve for angle C
- use the Sum of Angles Rule to find the other angle, B
- use The Law of Sines to solve for the last side, b
- Example:

- If
- For
**A < 90° (A < π/2)**:- If
**a ≥ c**there is 1 possible solution- use The Law of Sines to solve for angle C
- use the Sum of Angles Rule to find the other angle, B
- use The Law of Sines to solve for the last side, b
- Example:

- If
**a < c**we have 3 potential situations. "If**sin(A) < a/c**, there are two possible triangles satisfying the given conditions. If**sin(A) = a/c**, there is one possible triangle. If**sin(A) > a/c**, there are no possible triangles."^{[1]}**sin(A) < a/c**, there are two possible triangles

- solve for the 2 possible values of the 3rd side b = c*cos(A) ± √[ a
^{2}- c^{2}sin^{2}(A) ]^{[1]} - for each set of solutions, use The Law of Cosines to solve for each of the other two angles
- present 2 full solutions
- Example:

- solve for the 2 possible values of the 3rd side b = c*cos(A) ± √[ a
**sin(A) = a/c**, there is one possible triangle

- use The Law of Sines to solve for an angle, C
- use the Sum of Angles Rule to find the other angle, B
- use The Law of Sines to solve for the last side, b
- Example:

**sin(A) > a/c**, there are no possible triangles

- Error Notice: sin(A) > a/c so there are no solutions and no triangle!
- Example:

- If

- For
**SAS is Side, Angle, Side**- given the size of 2 sides (c and a) and the size of the angle B that is in between those 2 sides you can calculate the sizes of the remaining 1 side and 2 angles.- use The Law of Cosines to solve for the remaining side, b
- determine which side, a or c, is smallest and use the Law of Sines to solve for the size of the opposite angle, A or C respectively.
^{[2]} - use the Sum of Angles Rule to find the last angle

**SSS is Side, Side, Side**- given the sizes of the 3 sides you can calculate the sizes of all 3 angles in the triangle.- use The Law of Cosines to solve for the angles. You could also use the Sum of Angles Rule to find the final angle once you know 2 of them.

- In Degrees A + B + C = 180°
- In Radians A + B + C = π

If a, b and c are the lengths of the legs of a triangle opposite to the angles A, B and C respectively; then the law of sines states:

a/sin A = b/sin B = c/sin C

Solving, for example, for an angle, A = sin^{-1} [ a*sin(B) / b ]

If a, b and c are the lengths of the legs of a triangle opposite to the angles A, B and C respectively; then the law of cosines states:

a^{2} = c^{2} + b^{2} - 2bc cos A, solving for cos A, cos A = ( b^{2} + c^{2} - a^{2} ) / 2bc

b^{2} = a^{2} + c^{2} - 2ca cos B, solving for cos B, cos B = ( c^{2} + a^{2} - b^{2} ) / 2ca

c^{2} = b^{2} + a^{2} - 2ab cos C, solving for cos C, cos C = ( a^{2} + b^{2} - c^{2} ) / 2ab

Solving, for example, for an angle, A = cos^{-1} [ ( b^{2} + c^{2} - a^{2} ) / 2bc ]

Triangle perimeter, P = a + b + c

Triangle semi-perimeter, s = 0.5 * (a + b + c)

Triangle area, K = √[ s*(s-a)*(s-b)*(s-c)]

Radius of inscribed circle in the triangle, r = √[ (s-a)*(s-b)*(s-c) / s ]

Radius of circumscribed circle around triangle, R = (abc) / (4K)

[1] Weisstein, Eric W. "ASS Theorem." From *MathWorld*-- A Wolfram Web Resource. http://mathworld.wolfram.com/ASSTheorem.html

[2] Math is Fun - Solving SAS Triangles http://www.mathsisfun.com/algebra/trig-solving-sas-triangles.html

Zwillinger, Daniel (Editor-in-Chief). *CRC Standard Mathematical Tables and Formulae, 31st Edition* New York, NY: CRC Press, p. 512, 2003.

Weisstein, Eric W. "Triangle Properties." From *MathWorld*-- A Wolfram Web Resource. http://mathworld.wolfram.com/topics/TriangleProperties.html

**Dr. Math** at http://mathforum.org/library/drmath/view/54659.html

**Math is Fun** at http://www.mathsisfun.com/algebra/trig-solving-triangles.html

**Cite this content, page or calculator as:**

Furey, Edward "Triangle Theorems Calculator" From *http://www.CalculatorSoup.com* - Online Calculator Resource.